(xy-1)(x^2+y^2)=0

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Solution for (xy-1)(x^2+y^2)=0 equation: 


Simplifying
(xy + -1)(x2 + y2) = 0

Reorder the terms:
(-1 + xy)(x2 + y2) = 0

Multiply (-1 + xy) * (x2 + y2)
(-1(x2 + y2) + xy(x2 + y2)) = 0
((x2 * -1 + y2 * -1) + xy(x2 + y2)) = 0
((-1x2 + -1y2) + xy(x2 + y2)) = 0
(-1x2 + -1y2 + (x2 * xy + y2 * xy)) = 0

Reorder the terms:
(-1x2 + -1y2 + (xy3 + x3y)) = 0
(-1x2 + -1y2 + (xy3 + x3y)) = 0

Reorder the terms:
(xy3 + -1x2 + x3y + -1y2) = 0
(xy3 + -1x2 + x3y + -1y2) = 0

Solving
xy3 + -1x2 + x3y + -1y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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